RE: [sv-ec] Forever within always_comb

I'm not sure it should give a compiler error, but if not, it will result
in a zero-time infinite loop.

It is effectively the same as

always
  out1 = in1*in2 ;

To be useful, 'forever' needs a timing control, and timing controls ARE
illegal in always_comb.

Shalom

> -----Original Message-----
> From: owner-sv-ec@server.eda.org [mailto:owner-sv-ec@server.eda.org]
On
> Behalf Of Kakoli Bhattacharya
> Sent: Monday, October 23, 2006 12:40 PM
> To: sv-ec@server.eda.org
> Subject: [sv-ec] Forever within always_comb
> 
> Hello,
> 
> Is forever statement illegal within an always_comb block?
> 
>  always_comb
>   forever out1 = in1*in2;
> 
> Should the above eg give an error at compile time or at simulation?
> 
> Thanks,
> Kakoli