Shalom has given you the answer. Since you declared p to be type bit, it is 2-state. When you set it to 2'b1x, that is converted to 2-state, and it becomes 2'b10. Then {1'bx, p[0]} is 2'bx0, which will never match 2'b11. Steven Sharp sharp@cadence.com -- This message has been scanned for viruses and dangerous content by MailScanner, and is believed to be clean.Received on Thu Oct 16 10:14:36 2008
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