RE: [sv-ec] virtual methods

Thanks, I think I am getting the hang of this.

I don't see how the text I quoted from 8.19 was supposed to express this.

There are two more cases that I did not see explicitly described, unless I missed them.

In a case like this:

Leaf l = new;
Derived d = l;

1. From d, can I access a method M or property P that is defined in Leaf, but not in Derived? I understand that if M or P is defined in both Derived and then overriden in Leaf, then d.P (or M) gives me Derived::P (or M), not Leaf::P (or M), but is d.P (or M) legal if there is no Derived::P (or M)?

2. Declaring a method as virtual in Derived (e.g., pow()) means that d.pow() will give me Leaf::pow() instead of Derived::pow(). Is there any equivalent of a virtual method for properties? That is, if property P is defined in both Derived and Leaf, is there any way for d.P to give me Derived::P instead of Leaf::P? There does not seem to be.

Thanks,
Shalom



> -----Original Message-----
> From: David Jones [mailto:djones@xtreme-eda.com]
> Sent: Wednesday, December 31, 2008 6:49 PM
> To: Bresticker, Shalom
> Cc: sv-ec@server.eda.org
> Subject: Re: [sv-ec] virtual methods
>
> You're right. We do indeed get Derived::foo().
>
> Which just goes to show how confusing this can be to explain
> (but simple once you understand it).
>
> The task will be to come up with a good presentation for the next LRM.
>
> On Wed, Dec 31, 2008 at 11:41 AM, Bresticker, Shalom
> <shalom.bresticker@intel.com> wrote:
> > Hi,
> >
> >> d->foo(); // ditto. Here we must look up to pick up the
> >> definition in Base.
> >> l->foo(); // ditto.
> >
> > Since the reference types are Derived and Leaf,
> respectively, why don't we get Derived::foo() ?
> >
> > Thanks,
> > Shalom
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Intel Israel (74) Limited

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