Gordon, That is an interesting sophisticated example where the base class is not known until elaboration. I agree that there are some lexical ways for removing ambiguity in which scope to resolve a symbol (this, super). If we follow the normal verilog name resolution rules, in your example, since there is a child.i, i would resolve to child.i My opinion is that if there was an import p::*, then the parser needs to attempt to resolve the symbol by looking up in the package. The package look up is now part of name resolution as I had pointed out before. If the user needs to specify that i is a property of the class hierarchy, super.i needs to be used. If the symbol is not resolved at that point (no import and no static i), I would think that in your case we ought to consider 'i' as an oomr which may be resolved at elaboration. We should only consider this last resort because type of the immediate scope containing the symbol 'i' is not known until elaboration and i because it is a simple name needs to be resolved in that scope. That scope is not *complete* until elaboration. This is a new case of oomrs. Usually (with the exceptions of functions and tasks) an oomr consists of more than 1 token separated by '.' In summary, I expect the following: During parsing, normal Verilog name resolution rules (augmented by systemVerilog package look up) apply, then if the symbol is still undefined and the scope in which it appears is a type which is not known until elaboration, then the symbol is an oomr which is resolved at elaboration when the type is known. Another approach is to avoid the oomr for simple name and require that i be resolved at parsing time. However if super.i is used, allow the oomr to be resolved at elaboration. Francoise ' -----Original Message----- From: owner-sv-ec@eda.org [mailto:owner-sv-ec@eda.org] On Behalf Of Gordon Vreugdenhil Sent: Thursday, March 23, 2006 6:40 PM To: francoise martinolle Cc: sv-ec@eda.org Subject: Re: [sv-ec] question about name resolution in classes Francoise, This is an area that is quite a bit more interesting than even your example. The basic question is how to align lexical (and package) search rules with class member and property lookup. In the package case (such as yours), since the package is required to exist, the resolution of the base type is required to be known, so I think the intuitive answer is that "i" is the member reference and needs to be resolved as such. It isn't clear to me however that this is going to end up being the answer. There are other contexts which are far more difficult since there are separate compilation issues that come into play. Consider: module child; parameter type T = int; int i; class derived extends T; function void dump; $display(i); endfunction endclass endmodule package p; class base; bit b; endclass endpackage module top; class base; int i; endclas child #(base) c1(); child #(p::base) c2(); endmodule In this scenario, what does "i" mean in class derived? You can't possibly know what it is or whether it is even lexically resolved to child.i or resolved in the context of the class hierarchy. In my example, the answer changes in the different module instances. Since module child is a valid module for separate compilation there is no way to determine the answer at compilation; elaboration time is the earliest at which this can be resolved. This is complicated by the package import rules. If you didn't have "i" declared in "child" but it was potentially visible, would you do the import and make it actually visible? One reasonable approach to the general problem is to require a "this." or "super." prefix for references to inherited members in at least some situations. I don't think there is any ideal solution to the naming issue since you either have to deal with syntax requirements or have to try to define some reasonable rules for when an implementation is required to know things about the inheritance structure and when the user is required to disambiguate. This is loosely related to the issues with randomize() that Ray and I have been working on a proposal to address. Gord. francoise martinolle wrote: > Supposed I have a base class in a package and I create a derived class > of that class in a module. I do not import the package but I use the > package scope syntax to indicate the base class. Does this cause all > the class item declaration of the BASE class to be visible in the > derived class? > > I think it should. > > > package p; > class BASE; > rand logic i; > endclass > endpackage > > > module top; > class derived extends p::BASE; > constraint c1 { i == 1'b1}; > endclass > endmodule > -- -------------------------------------------------------------------- Gordon Vreugdenhil 503-685-0808 Model Technology (Mentor Graphics) gordonv@model.comReceived on Thu Mar 23 19:17:08 2006
This archive was generated by hypermail 2.1.8 : Thu Mar 23 2006 - 19:17:14 PST