There is one difference. You're correct that the bit representations are the same. But the interpretations of the results when used are different, one is signed and the other is unsigned. Shalom > The situation and result should be the same as scenario 2. > The only significant difference between myreg and byte is > that myreg is 4-state and byte is 2-state, which doesn't > matter here since the values are in the 2-state value set. > The situation here is the same as scenario 1, and so is the > result. As in scenario 1, the operands of the subtract are unsigned. --------------------------------------------------------------------- Intel Israel (74) Limited This e-mail and any attachments may contain confidential material for the sole use of the intended recipient(s). Any review or distribution by others is strictly prohibited. If you are not the intended recipient, please contact the sender and delete all copies. -- This message has been scanned for viruses and dangerous content by MailScanner, and is believed to be clean.Received on Tue May 13 06:07:00 2008
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