Re: [sv-bc] Sign of a signed packed array of struct

Shalom,

I find it ambiguous whether this "packed array is declared as signed":

    struct packed signed { ... } [3:0] S;

It *looks* like the packed struct is declared as signed, but then I see the little range tucked in at the end of the declaration. Does this mean that the array is declared as signed and the struct is *not* declared as signed? Just because the struct is unnamed does not mean that the signed keyword should not apply to it.

Paul
----- Original Message -----
From: "Shalom Bresticker" <shalom.bresticker@intel.com>
To: "Paul Graham" <pgraham@oasys-ds.com>, "sv-bc" <sv-bc@eda.org>
Sent: Friday, October 15, 2010 8:14:32 AM
Subject: RE: [sv-bc] Sign of a signed packed array of struct

7.4.1 says,

"If a packed array is declared as signed, then the array viewed as a single vector shall be signed. The individual elements of the array are unsigned unless they are of a named type declared as signed. A part-select of a packed array shall be unsigned."

So I would assume S to be signed and S[0] as unsigned.

Shalom

> -----Original Message-----
> From: owner-sv-bc@eda.org [mailto:owner-sv-bc@eda.org] On Behalf Of
> Paul Graham
> Sent: Saturday, September 11, 2010 12:11 AM
> To: sv-bc
> Subject: [sv-bc] Sign of a signed packed array of struct
>
> Given this array-of-struct declaration:
>
> struct packed signed { ... } [3:0] S;
>
> I can't tell if the signed keyword applies to the struct or to the
> array as a whole. Is S signed? Is S[0] signed?
>
> Paul

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